포인터 관련 퍼즐인데 답을 보고도 이해가 안되네요

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 #include <stdio.h>
 
int main()
{   
    int *a[] = {0,1,2,3,4};
 
    printf("arr0=%d\n", *a+0);
    printf("arr1=%d\n", *a+1);
    printf("arr2=%d\n", *a+2);
    printf("arr3=%d\n", *a+3);
    printf("arr4=%d\n", *a+4);
 
    return 0;
}

이렇게 하면 결과가

arr0=0 arr1=4 arr2=8 arr3=12 arr4=16

결과가 이렇게 나온다는데

설명을 봐도 전혀 이해가 안되네요.

기계어로는 

000000000040052d <main>:
  40052d:	55                   	push   %rbp
  40052e:	48 89 e5             	mov    %rsp,%rbp
  400531:	48 83 ec 30          	sub    $0x30,%rsp
  400535:	48 c7 45 d0 00 00 00 	movq   $0x0,-0x30(%rbp)			# placing array onto stack
  40053c:	00 
  40053d:	48 c7 45 d8 00 00 00 	movq   $0x0,-0x28(%rbp)
  400544:	00 
  400545:	48 c7 45 e0 00 00 00 	movq   $0x0,-0x20(%rbp)
  40054c:	00 
  40054d:	48 c7 45 e8 00 00 00 	movq   $0x0,-0x18(%rbp)
  400554:	00 
  400555:	48 c7 45 f0 00 00 00 	movq   $0x0,-0x10(%rbp)
  40055c:	00 
  40055d:	48 8b 45 d0          	mov    -0x30(%rbp),%rax			# move first array value to rax register
  400561:	48 89 c6             	mov    %rax,%rsi				# no add just move rax value
  400564:	bf 94 06 40 00       	mov    $0x400694,%edi
  400569:	b8 00 00 00 00       	mov    $0x0,%eax
  40056e:	e8 9d fe ff ff       	callq  400410 <printf@plt>
  400573:	48 8b 45 d0          	mov    -0x30(%rbp),%rax			# move first array value to rax register
  400577:	48 83 c0 04          	add    $0x4,%rax				# add 4 to the value in the rax register
  40057b:	48 89 c6             	mov    %rax,%rsi
  40057e:	bf 9d 06 40 00       	mov    $0x40069d,%edi
  400583:	b8 00 00 00 00       	mov    $0x0,%eax
  400588:	e8 83 fe ff ff       	callq  400410 <printf@plt>
  40058d:	48 8b 45 d0          	mov    -0x30(%rbp),%rax			# move first array value to rax register
  400591:	48 83 c0 08          	add    $0x8,%rax				# add 8 to the value in the rax register
  400595:	48 89 c6             	mov    %rax,%rsi
  400598:	bf a6 06 40 00       	mov    $0x4006a6,%edi
  40059d:	b8 00 00 00 00       	mov    $0x0,%eax
  4005a2:	e8 69 fe ff ff       	callq  400410 <printf@plt>
  4005a7:	48 8b 45 d0          	mov    -0x30(%rbp),%rax			# move first array value to rax register
  4005ab:	48 83 c0 0c          	add    $0xc,%rax				# add 12 to the value in the rax register
  4005af:	48 89 c6             	mov    %rax,%rsi
  4005b2:	bf af 06 40 00       	mov    $0x4006af,%edi
  4005b7:	b8 00 00 00 00       	mov    $0x0,%eax
  4005bc:	e8 4f fe ff ff       	callq  400410 <printf@plt>
  4005c1:	48 8b 45 d0          	mov    -0x30(%rbp),%rax			# move first array value to rax register
  4005c5:	48 83 c0 10          	add    $0x10,%rax				# add 16 to the value in the rax register
  4005c9:	48 89 c6             	mov    %rax,%rsi
  4005cc:	bf b8 06 40 00       	mov    $0x4006b8,%edi
  4005d1:	b8 00 00 00 00       	mov    $0x0,%eax

이렇다는데 a가 포인터의 배열이라는 것도 알겠고, 

a에 값이 0, 1, 2, 3, 4가 들어간다는 말도 알겠는데

어떻게 저런 결과가 나오는지는 이해가 안되는군요.

혹시 이 퍼즐이 이해가 되시는 능력자분이 있을까요?